Assume Gs = 2.65 (typical) e = (Gs·ρw/ρd) – 1 = (2.65×1/1.647) – 1 = 0.609
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Mass of water = 176 – 140 = 36 g Water content w = (36/140) × 100 = 25.7% Bulk density ρ = 176/85 = 2.07 g/cm³ Dry density ρd = 140/85 = 1.647 g/cm³ Assume Gs = 2
(step-by-step as Sutton would present):